A sample of metal weighs $210 gm$ in air, $180 gm$ in water and $120 gm$ in liquid. Then relative density $(RD) $ of
AMetal is $3$
BMetal is $7$
CLiquid is $3$
DBoth $(b) $ and $(c)$
Diffcult
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DBoth $(b) $ and $(c)$
d (d) Density of metal = $\rho $, Density of liquid = $\sigma$
If $ V$ is the volume of sample then according to problem
$210 = V\rho g$…(i)
$180 = V(\rho - 1)g$…(ii)
$120 = V(\rho - \sigma )g$…(iii)
By solving (i), (ii) and (iii) we get $\rho = 7$ and $\sigma = 3$.
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