MCQ
A satellite moves around the earth in a circular orbit of radius $r$ with speed $v$. If the mass of the satellite is $M$, its total energy is
  • $ - \frac{1}{2}M{v^2}$
  • B
    $\frac{1}{2}M{v^2}$
  • C
    $\frac{3}{4}M{v^2}$
  • D
    $M{v^2}$

Answer

Correct option: A.
$ - \frac{1}{2}M{v^2}$
a
(a) Total energy = $-$ (kinetic energy) = $ - \frac{1}{2}M{v^2}$

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