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STD 11 - 2. motion in straight line — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETSTD 11 - 2. motion in straight line4 Marks
MCQ
A scooter accelerates from rest for time $t_{1}$ at constant rate $a _{1}$ and then retards at constant rate $a _{2}$ for time $t _{2}$ and comes to rest. The correct value of $\frac{t_{1}}{t_{2}}$ will be ..... .
  • A
    $\frac{a_{1}+a_{2}}{a_{2}}$
  • ✓
    $\frac{ a _{2}}{ a _{1}}$
  • C
    $\frac{ a _{1}}{ a _{2}}$
  • D
    $\frac{a_{1}+a_{2}}{a_{1}}$
✓

Answer

Correct option: B.
$\frac{ a _{2}}{ a _{1}}$
b
Draw vt curve

$\tan \theta_{1}=a_{1}=\frac{v_{\max }}{t_{1}}$ And $\tan \theta_{2}=a_{2}=\frac{v_{\max }}{t_{2}}$

$\div$ above

$\frac{t_{1}}{t_{2}}=\frac{a_{2}}{a_{1}}$

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