- Must be less than 10cm.
- Must be greater than 20cm.
- Must not be greater than 20cm.
- Must not be less than 10cm.
Explanation:
$\text{v}=(40-4)$
$\frac{1}{\text{f}}=\frac{1}{40-4}-\frac{1}{(-\text{u})}$
$\frac{\text{df}}{\text{du}}=0$ for f minimum.
$\frac{\text{df}}{\text{du}}=1-\frac{\text{u}}{20}=0$
$\text{u}=20$
$\text{f}_{\text{min}}=10\text{cm}$
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(a) 25 |
(b) -12.5 |
(c) -25 |
(d) 12.5 |
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(a) Potential at A = Potential at B |
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(b) Total electric field flux through the surface of the cavity is q/ |
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(c) Electric field near A in the cavity = Electric field near B in the cavity |
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