A screwgauage has pitch $1.5\; mm$ and there is no zero error. Linear scale has marking at $MSD = 1\; mm$ and there are $100$ equal division of circular scale. When diameter of a sphere is measured with instrument, main scale is having $2\; mm$ mark visible on linear scale, but $3\; mm$ mark is not visible, $76^{th}$ division of circuler scale is in line with linear scale. .......... $mm$ is the diameter of sphere.
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