MCQ
A sequence $a, a+d, a+2 d, \ldots, a+n d$, has odd number of terms. Find its median.
  • A
    $a+\left(\frac{n-1}{2}\right) d$
  • B
    $a+\left(\frac{n}{2}-1\right) d$
  • $a+\left(\frac{n+2}{2}\right) d$
  • D
    $a+\left(\frac{n}{2}+2\right) d$

Answer

Correct option: C.
$a+\left(\frac{n+2}{2}\right) d$
(c) : Clearly, the given sequence is an A.P. with first term $a$ and common difference is $d$. Given, sequence is $a, a+d, a+2 d, a+3 d, \ldots, a+n d$ As, there are odd number of terms, so the median is
$
\left(\frac{n+1+1}{2}\right)^{\text {th }} \text { term }=\left(\frac{n+2}{2}\right)^{\text {th }} \text { term }=a+\left(\frac{n+2}{2}\right) d
$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free