A set of $20$ tuning forks is arranged in a series of increasing frequencies. If each fork gives $4$ beats with respect to the preceding fork and the frequency of the last fork is twice the frequency of the first, then the frequency of last fork is $\dots \; Hz$.
JEE MAIN 2022, Diffcult
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$f_{1}= f$
$f _{2}= f +4$
$f _{3}= f +2 \times 4$
$f _{4}= f +3 \times 4$
$f _{20}= f +19 \times 4$
$f +(19 \times 4)=2 \times f$
$f =76 \; Hz$
Frequency of last tuning forks $=2 \; f$
$=152 \; Hz$
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