Question
A side of an equilateral triangle is 20cm long. A second equilateral triangle is inscribed in it by joining the mid-points of the sides of the first triangle. This process is continued for third, fourth, fifth, triangles. Find the perimeter of the sixth inscribed equilateral triangle.

Answer

Let the given equilateral triangle be $\triangle\text{ABC}$ with each side of 20cm.
By joining the mid-points of this triangle, we get another equilateral triangle of side equal to half of the length of side of $\triangle\text{ABC.}$
Continuing in this way, we get a set of equilateral triangles with side equal to half of the side of the previous triangle.
Now,
Perimeter of first triangle = 20 × 3 = 60cm;
Perimeter of second triangle = 10 × 3 = 30cm;
Perimeter of third triangle = 5 × 3 = 15cm;
Clearly 60, 30, 15 ...., from a G.P. with a = 60 and $\text{r}=\frac{30}{60}=\frac{1}{2}.$
We have, tofind perimeter of sixth incribed triangle i.e., we have to fiind the sixth term of the G.P.
$\therefore$ Perimeter of sixth incribed triangle
$\text{a}_6=\text{ar}^{6-1}=60\times\Big(\frac{1}{2}\Big)^5=\frac{60}{32}=\frac{15}{8}\text{cm}$

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