MCQ
A simple pendulum of length $l$ has maximum angular displacement $\theta$. The maximum kinetic energy of the bob of mass $m$ is ( $g=$ acceleration due to gravity)
  • A
    $m g l(1+\cos \theta)$
  • B
    $m g l\left(1+\cos ^2 \theta\right)$
  • $m g l(1-\cos \theta)$
  • D
    $m g l(\cos \theta-1)$

Answer

Correct option: C.
$m g l(1-\cos \theta)$
(c) : Refer to the figure.
Maximum kinetic energy of the bob $=$ total energy of the bob $=$ maximum potential energy of the bob
$
\begin{aligned}
& =m g h=m g(l-l \cos \theta) \\
& =m g l(1-\cos \theta)
\end{aligned}
$
Image

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