$\frac{\lambda}{4}$
$\frac{\lambda}{3}$
$\frac{\lambda}{2}$
$\lambda.$
$\frac{\lambda}{2}$
Explanation:
A sine wave has a maxima and a minima and the particle displacement has phase difference of $\pi$ radians. Therefore, applying similar argument we can say that if a particular particle has zero displacement at a certain instant. then the particle closest to it having zero displacement is at a distance is equal to $\frac{\lambda}{2}.$
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(b) 
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(c) 
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(a) 40 |
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(a) i = 0.5 A |
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