A single circular loop of radius $1.00\, m$ carries a current of $10.0\, mA$. It is placed in $a$ uniform magnetic field of magnitude $0.500\, T$ that is directed parallel to the plane of the loop as suggested in the figure. The magnitude of the torque exerted on the loop by the magnetic field is.
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$\vec {\tau}=\vec {\mu} \times \vec {\mathrm{B}}$
$\tau=\mu \mathrm{B} \sin \theta$
$\tau=\mu \mathrm{B}=\mathrm{I} \mathrm{AB}$
$\tau=I\left(\pi \mathrm{r}^{2}\right) \mathrm{B}$
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