A slab X is placed between the two parallel isolated charged plat… - Vidyadip

MCQ

A slab $X$ is placed between the two parallel isolated charged plates as shown in the figure. If $E_p$ and $E_q$ denotes the intensity of electric field at $P$ and $Q$, then:

A
$E_p$ is reduced by the presence of $X$, if $X$ is metallic.
B
$E_q$ is increased by presence of $X$, if $X$ is dielectric.
C
$E _{ q }$ is in the opposite sense to $E _{ p ^{\prime}}$ if X is dielectric.
✓
$E_q$ is zero, if $X$ is metallic.

✓

Answer

Correct option: D.

$E_q$ is zero, if $X$ is metallic.

d. $E_q$ is zero, if $X$ is metallic.
Explanation:
There is no effect of the metal on the external electric field(thus $A$ is incorrect) while the dielectric reduces the net electric field outside. The dielectric produces an electric field inside it due to the induced charges which is opposite to the external field. Thus $EQ$ is reduced and B and $C$ are also incorrect.(Note that $E_p$ is not the external field). Now as the electric field inside the conductor is zero, the field $E_p$ is zero if $X$ is a metallic.

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