- A$6.2$
- ✓$6.3$
- C$6.4$
- D$6.5$
$v =\frac{ dS }{ dt }= v _0 e ^{- t / t }$
$\int_0^{ s } dS = v _0 \int_0^\tau e ^{- t / t } dt$
$\Delta S = v _0\left[-\tau e ^{- t / \tau }\right]_0^{ t }$
$\Delta S = v _0 \tau\left[1-\frac{1}{ e }\right]$
$\text { Impulse }=\Delta P = m \Delta v$
$\Delta v =\frac{1}{0.4}=2.5$
$\Delta s =4 \times 2.5[1-0.37]=10 \times 0.63=6.3 m / s$
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$[A]$ A dark spot will be formed at the point $\mathrm{P}_2$
$[B]$ At $P_2$ the order of the fringe will be maximum
$[C]$ The total number of fringes produced between $P_1$ and $P_2$ in the first quadrant is close to $3000$
$[D]$ The angular separation between two consecutive bright spots decreases as we move from $P_1$ to $P_2$ along the first quadrant