- A$I_2$ will be reduced to $I^-$
- Bthere will be no redox reaction
- ✓$I^-$ will be oxidised to $I_2$
- D$Fe^{2+}$ will be oxidised to $Fe^{3+}$
If $\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}(=+0.77 \mathrm{V})$ is greater than that of $I_{2} / 2 \mathrm{I}^{-}(=0.536 \mathrm{V}),$ Fe $^{3+}$ will be reduced to $\mathrm{Fe}^{2+}$ and $I^-$ will be oxidised to $I_2$.
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In the above first order reaction the concentration of $\mathrm{PCl}_{5}$ reduces from initial concentration $50\, mol\,\mathrm{L}^{-1}$ to $10\, \mathrm{~mol} \,\mathrm{~L}^{-1}$ in $120\, minutes$ at $300\, \mathrm{~K}$. The rate constant for the reaction at $300\, \mathrm{~K}$ is $\mathrm{X}$ $\times 10^{-2} \mathrm{~min}^{-1}$. The value of $x$ is $......$
$[$ Given $\log 5=0.6989]$
$[I]$ Only $A, B$ and $C$ react with $1\,M\,HCl$ to give $H_2\,(g)$
$[II]$ When $C$ is added to solutions of the other metal ions, metallic $B$ and $D$ are formed.
$[III]$ Metal $C$ does not reduce $A^{n+}$