MCQ
A solution contains $Fe^{2+}, Fe^{3+}$ and $ I^-$ ions. This solution was treated with iodine at $35^oC.$  $E^o$ for $Fe^{3+} /Fe^{2+}$ is $+ 0.77\, V$ and $E^o$ for $I_2/2I^- = 0.536\, V.$ The favourable redox reaction is
  • A
    $I_2$ will be reduced to $I^-$
  • B
    there will be no redox reaction
  • $I^-$ will be oxidised to $I_2$
  • D
    $Fe^{2+}$ will be oxidised to $Fe^{3+}$

Answer

Correct option: C.
$I^-$ will be oxidised to $I_2$
c
Greater the value of reduction potential, greater will be its tendency, to get reduced. Since the reduction potential value $\cdot$

If $\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+}(=+0.77 \mathrm{V})$ is greater than that of $I_{2} / 2 \mathrm{I}^{-}(=0.536 \mathrm{V}),$ Fe $^{3+}$ will be reduced to $\mathrm{Fe}^{2+}$ and $I^-$ will be oxidised to $I_2$. 

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