A solution of alcohol in water has been prepared by mixing
$100\ ml$ of alcohol in $300\ mL$ of water. Calculate the volume percentage of the solution.
$100\ ml$ of alcohol in $300\ mL$ of water. Calculate the volume percentage of the solution.
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Percent by volume $=\frac{\text{volume of solute}}{\text{Volume of solution}}\times100$
Volume of solution $= 100+300 = 400\ ml$
$ \%$ volume$ = 100\ ml$ (alcohol)/ $400$ (solution) $x 100 \% = 25 \%.$
Volume of solution $= 100+300 = 400\ ml$
$ \%$ volume$ = 100\ ml$ (alcohol)/ $400$ (solution) $x 100 \% = 25 \%.$
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