Question
A SONAR system fixed in a submarine operates at a frequency 40.0 kHz. An enemy submarine moves towards the SONAR with a speed of 360km h–1. What is the frequency of sound reflected by the submarine? Take the speed of sound in water to be 1450m s–1.

Answer

The frequency of SONAR received by enemy submarine will be further reflected back to SONAR which it will receive again with a different frequency.
SONAR frequency(Vs) = 40kHz = 40 × 103Hz
Speed of enemy submarine(Vo) = 360km/h
$=360\times\frac{5}{18}=100\text{m/s}$
Speed of sound in water = 1450m/s
Apparent frequency received by submarine is
$\text{f}'=\Big\{\frac{\text{V}+\text{V}_\text{o}}{\text{V}}\Big\}\text{f}=\Big\{\frac{1450+100}{1450}\Big\}\times40=42.76\text{kHz}$
Now, the reflected wave have a different frequency,
$\text{f}"=\Big\{\frac{\text{V}}{\text{V}-\text{V}_\text{o}}\Big\}\text{f}'=\Big\{\frac{1450}{1450-100}\Big\}\times42.76=45.93\text{kHz}$

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