A source and an observer approach each other with same velocity $50 m/s$. If the apparent frequency is $435 \,s^{-1}$, then the real frequency is .... $s^{-1}$
Medium
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(a) $n' = n\left[ {\frac{{v + {v_O}}}{{v - {v_S}}}} \right];$
Here $v = 332$m/s and ${v_0} = {v_s} = 50 m/s$
$ \Rightarrow $$435 = n\left[ {\frac{{332 + 50}}{{332 - 50}}} \right]$
$\Rightarrow n = 321.12\,\,se{c^{ - 1}} \approx 320\,se{c^{-1}}$
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