- ✓$\frac{{C + \,u}}{f}$
- B$\frac{{C - u}}{f}$
- C$\frac{{C\left( {C + u} \right)}}{{\left( {C - u} \right)f}}$
- D$\frac{C}{f}$
where $v_{s}$ is the velocity of sound $w.r.t$ medium and $v_{m}$ is the velocity of the medium.
Thus $v^{\prime}=C+u$
As both the source as well as the observer are at rest, so frequency will remain the same as $f$ irrespective of the velocity of medium.
Let $\lambda$ be the wavelength of the sound wave detected by observer.
using, $v^{\prime}=f \times \lambda$
$C+u=f \lambda \Longrightarrow \lambda=\frac{C+u}{f}$
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$(A)$ a high-pressure pulse starts traveling up the pipe, if the other end of the pipe is open.
$(B)$ a low-pressure pulse starts traveling up the pipe, if the other end of the pipe is open.
$(C)$ a low-pressure pulse starts traveling up the pipe, if the other end of the pipe is closed.
$(D)$ a high-pressure pulse starts traveling up the pipe, if the other end of the pipe is closed.