$=\sigma A\left(T^{4}-T_{0}^{4}\right)=-\sigma 4 \pi r^{2}\left(T_{0}^{4}-T^{4}\right)$
$=\frac{d(m L)}{d t}=\rho L \frac{d v}{d t}=\rho L 4 \pi r^{2} \frac{d r}{d t}$
$\Rightarrow-\sigma 4 \pi r^{2}\left(T_{0}^{4}-T^{4}\right)=\sigma L 4 \pi r^{2} \frac{d r}{d t}$
$\Rightarrow$ radius decreases with time




$Reason :$ The thermal conductivity of brass is more than the thermal conductivity of wood.