Question
A square and an equilateral triangle have a side in common. If side of triangle is $\frac{4}{3}\text{cm}$ long find the perimeter of figure formed (Fig).
✓
Answer
As square and equilateral triangle both have a common side, i.e. $BC$
So, all the sides of square and trangle will be equal and of measure $\frac{4}{3}\text{cm}$
$\therefore$ Perimeter of the figure $= AB + BD + DE + EC + AC$
$5 \times AB [$since, all the lengths are equal$]$
$=5\times\frac{4}{3}$
$=\frac{20}{3}\text{cm}.$
So, all the sides of square and trangle will be equal and of measure $\frac{4}{3}\text{cm}$
$\therefore$ Perimeter of the figure $= AB + BD + DE + EC + AC$
$5 \times AB [$since, all the lengths are equal$]$
$=5\times\frac{4}{3}$
$=\frac{20}{3}\text{cm}.$
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