Question
A square loop, carrying a steady current $I,$ is placed in a horizontal plane near a long straight conductor carrying a steady current $I_1$ at a distance $d$ from the conductor as shown in figure. The loop will experience

Answer

$F_{2}=-F_{4}$

$F_{1}=\frac{\mu_{0} I_{1} \Pi}{2 \pi d l}$

$F_{2}=\frac{\mu_{0} I_{1} I}{2 \pi(d+l)}$

$F_{1}>F_{3}$

$F_{n e t}=F_{1}-F_{3}$

So, wire attract loop.

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