A standing wave pattern of amplitude $A$ in a string of length $L$ shows $2$ nodes (plus those at two ends). If one end of the string corresponds to the origin and $v$ is the speed of progressive wave, the disturbance in the string, could be represented (with appropriate phase) as:
Diffcult
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From the given information, there are four nodes of the wave( $n=4$ ), including the two at the ends. Clearly, it forms a sine wave. With amplitude $A,$ wave number, $k=$ $(n-1) \pi / L=3 \pi / L .$ Writing this in the standard sinusoidal standing wave form, $y=$
$A \sin (k x) \cos (\omega t)$
$\omega=k v$
$y=A \sin (3 \pi x / L) \cos (3 \pi v t / L)$
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