MCQ
A stone is projected in air. Its time of flight is $3\,s$ and range is $150\,m$ Maximum height reached by the stone is $......\,m$ $\left(g=10\,ms ^{-2}\right)$
- A$37.5$
- B$22.5$
- C$90$
- ✓$11.25$
$T=\frac{2 u_y}{g}=3$
$\therefore \quad u_y=15\,m / s$
Now,
$H=\frac{u_y^2}{2 g}=\frac{(15)^2}{20}=11.25\,m$
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| Column $I$ | Column $II$ |
| $(A)$ Horizontal component of velocity | $(p)$ $5$ SI unit |
| $(B)$ Vertical component of velocity | $(q)$ $10$ SI unit |
| $(C)$ Horizontal displacement | $(r)$ $15$ SI unit |
| $(D)$ Vertical displacement | $(s)$ $20$ SI unit |