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Question Bank [ 2022 ] — Physics STD 12 Science — Question

Maharashtra BoardEnglish MediumSTD 12 SciencePhysicsQuestion Bank [ 2022 ]1 Mark
Question
A string 1 m long is fixed at one end. The other end is moved up and down with a frequency of 20 Hz. Due to this, a stationary wave with four complete loops gets produced on the string. Find the speed of the progressive wave which produces the stationary wave.
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Answer

$L =1 m , n =20 Hz$
Since an antinode is formed at the free end.
Thus, with four and a half loops of the string,
$L =\frac{\lambda}{4}+2 \lambda=\frac{9}{4} \lambda$
$\therefore \lambda=\frac{4 L }{9}=\frac{4}{9} \times 1=\frac{4}{9} m$
$\therefore v = n \lambda$
$=20 \times \frac{4}{9}$
$=8.88 m / s$

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