A student is provided with a variable voltage source $V$, a test resistor $R_T=10\,\Omega$, two identical galvanometers $G_1$ and $G_2$ and two additional resistors, $R _1=10\,M\,\Omega$ and $R _2=0.001\,\Omega$. For conducting an experiment to verify ohms law, the most suitable circuit is:
- A
- B
- C
- D
JEE MAIN 2023, Medium
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A $100\, W$ bulb $B_1$, and two $60\,W$ bulbs $B_2$ and $B_3$, are connected to a $250\, V$ source, as shown in the figure. Now $ W_1, W_2$ and $W_3$ are the output powers of the bulbs $B_1, B_2$ and $B_3$, respectively. ThenView Solution
- 2A wire of radius $r$ has resistance $R$. If it is stretched to a radius of $\frac{{3r}}{4}$, its resistance becomesView Solution
- 3Calculate the amount of charge flowing in $2$ minutes in a wire of resistance $10$ $\Omega$ when a potential difference of $20\,V$ is applied between its ends ............ $C$View Solution
- 4View SolutionOhm's law fails in
- 5In the arrangement of resistances shown below, the effective resistance between points $A$ and $B$ is ............... $\Omega$View Solution
- 6View SolutionOn increasing the temperature of a conductor, its resistance increases because
- 7The heat generated through $2 \,ohm$ and $8\, ohm$ resistances separately, when a condenser of $200\,\mu F$ capacity charged to $200\, V$ is discharged one by one, will beView Solution
- 8A meter bridge is set-up as shown, to determine an unknown resistance ' $X$ ' using a standard $10$ ohm resistor. The galvanometer shows null point when tapping-key is at $52 \ cm$ mark. The end-corrections are $1 \ cm$ and $2 \ cm$ respectively for the ends $A$ and $B$. The determined value of ' $X$ ' isView Solution
- 9A steady current $I$ is set up in a wire whose cross-sectional area decreases in the direction of the flow of the current. Then, as we examine the narrowing region,View Solution
- 10In the circuit shown, current (in $A$) through $50\; V$ and $30\; V$ batteries are, respectivelyView Solution
