MCQ
A student performs a titration with different burettes and finds titre values of $25.2 \mathrm{~mL}, 25.25 \mathrm{~mL}$ and $25.0$ $\mathrm{mL}$. The number of significant figures in the average titre value is
- ✓$3$
- B$2$
- C$1$
- D$9$
✓
Answer
Correct option: A.
$3$
a
We have $25.20,25.25$ and $25.00$ ml .
We have $25.20,25.25$ and $25.00$ ml .
$\text { Average }=\frac{25.20+25.25+25.00}{3}$
$=\frac{75.45}{3}$
$=25.15=25.1$
In case of division, the final answer will contain as many significant figures as there are in an number with least significant numbers.
So, the significant number is $3$ .
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