A submarine experiences a pressure of $5.05\times 10^6\,Pa$ at a depth of $d_1$ in a sea. When it goes further to a depth of $d_2,$ it experiences a pressure of $8.08\times 10^6\,Pa.$ Then $d_2 -d_1$ is approximately ........ $m$ (density of water $= 10^3\,kg/m^3$ and acceleration due to gravity $= 10\,ms^{-2}$ )
A$400$
B$500$
C$600$
D$303$
JEE MAIN 2019, Medium
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D$303$
d ${P_1} = 5.05 \times {10^6}\,;\,{P_2} = 8.08 \times {10^6}$
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