Question
A telescope has an objective of diameter $2.44 m$. What is its angular resolution when it observes at $5500 A$ ?

Answer

Data : $\lambda=5500 A =5.5 \times 10^{-7} m$.
$D =2.44 m$
Angular resolution. $\Delta \theta=1.22 \lambda / D, D$ being the diameter of the aperture.
$\therefore \Delta \theta=1.22 \times 5.5 \times \frac{10^{-7}}{2.44}=2.75 \times 10^{-7} rad$
$=0.0567$ arcsec

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