Question
A telescope has an objective of diameter 2.5 m . What is its angular resolution when observed at 7500 Å?

Answer

Given: $\lambda=7500$, A=$7.5 \times 10^{-7} m$,, $a=2.5 m, \quad \theta=?$
Formula: $\theta=\frac{1.22 \lambda}{a}$
$\begin{array}{ll}
\therefore & \theta=\frac{1.22 \times 7.5 \times 10^{-7}}{2.5}=1.22 \times 3 \times 10^{-7} \\
\therefore & m=3.66 \times 10^{-7} rad\end{array}$

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