MCQ
A thin uniform, circular ring is rolling down an inclined plane of inclination $30^o$ without slipping. Its linear acceleration along the inclined plane will be
- A$\frac {g}{2}$
- B$\frac {g}{3}$
- ✓$\frac {g}{4}$
- D$\frac {2g}{3}$
✓
Answer
Correct option: C.
$\frac {g}{4}$
c
$a=\frac{g \sin \theta}{1+k^{2} / R^{2}}=\frac{g \sin 30^{\circ}}{1+1}=\frac{g / 2}{2}=\frac{g}{4}$
$a=\frac{g \sin \theta}{1+k^{2} / R^{2}}=\frac{g \sin 30^{\circ}}{1+1}=\frac{g / 2}{2}=\frac{g}{4}$
$\left(\frac{\mathrm{k}^{2}}{\mathrm{R}^{2}}\right) \operatorname{ring}=1$
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