MCQ
A train is moving along a straight line with a constant acceleration ' $a$ '. A boy standing in the train throws a ball forward with a speed of $10 \ m / s$, at an angle of $60^{\circ}$ to the horizontal. The boy has to move forward by $1.15 \ m$ inside the train to catch the ball back at the initial height. The acceleration of the train, in $m / s ^2$, is
  • $5$
  • B
    $6$
  • C
    $7$
  • D
    $8$

Answer

Correct option: A.
$5$
a
Ball performs parabolic motion,

For vertical motion,

$s = ut -\frac{1}{2} g t ^2$

$\therefore o =10 \sin 60^{\circ} t -\frac{1}{2} \times 10 \times t ^2$

$\therefore t =\sqrt{3} s$

For horizontal motion,

$s=u t+\frac{1}{2} a t^2$

$\therefore 1.15=10 \cos 60^{\circ} \times \sqrt{3}-\frac{1}{2} a (3)$

$\therefore a=5 \ m / s ^2$

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