- ✓$5$
- B$6$
- C$7$
- D$8$
For vertical motion,
$s = ut -\frac{1}{2} g t ^2$
$\therefore o =10 \sin 60^{\circ} t -\frac{1}{2} \times 10 \times t ^2$
$\therefore t =\sqrt{3} s$
For horizontal motion,
$s=u t+\frac{1}{2} a t^2$
$\therefore 1.15=10 \cos 60^{\circ} \times \sqrt{3}-\frac{1}{2} a (3)$
$\therefore a=5 \ m / s ^2$
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[Given: Mass of neutron/proton $=(5 / 3) \times 10^{-27} kg$, charge of the electron $=1.6 \times 10^{-19} C$.]
Which of the following option($s$) is(are) correct?
$(A)$ The value of $x$ for $H^{+}$ion is $4 cm$.
$(B)$ The value of $x$ for an ion with $A_M=144$ is $48 cm$.
$(C)$ For detecting ions with $1 \leq A_M \leq 196$, the minimum height $\left(x_1-x_0\right)$ of the detector is $55 cm$.
$(D)$ The minimum width $w$ of the region of the magnetic field for detecting ions with $A_M=196$ is $56 cm$.

