Question
A train starting from stationary position and moving with uniform acceleration attains a speed of 36km per hour in 10 minutes. Find its acceleration.
✓
Answer
Initial velocity, u = 0m/s
Final velocity, v = 36km/h = 10m/s
Time, t = 10min = 10 x 60 = 600 sec
Acceleration, a = ?
Acceleration $=\frac{\text{Final velocity-Initial velocity}}{\text{time taken}}$
So, $\text{a}=\frac{\text{v-u}}{\text{t}}$
$=\frac{10-0}{600}=\frac{10}{600}\text{m/s}^2$
$=\frac{1}{60}\text{m/s}^2-0.16\text{m/s}^2$
Final velocity, v = 36km/h = 10m/s
Time, t = 10min = 10 x 60 = 600 sec
Acceleration, a = ?
Acceleration $=\frac{\text{Final velocity-Initial velocity}}{\text{time taken}}$
So, $\text{a}=\frac{\text{v-u}}{\text{t}}$
$=\frac{10-0}{600}=\frac{10}{600}\text{m/s}^2$
$=\frac{1}{60}\text{m/s}^2-0.16\text{m/s}^2$
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