MCQ
A transistor has a current amplification factor of $60$ . In a $CE$ amplifier, input resistance is $1 \,k \Omega$ and output voltage is $0.01 \,V$. The transconductance is (in $SI$ units)
- A$10^{-5}$
- ✓$6 \times 10^{-2}$
- C$6 \times 10^4$
- D$10$
$\beta=\frac{\Delta I_C}{\Delta I_B}=60 \quad R_i=1 \,k \Omega, V_0=0.01\, V$
$g m=\frac{\beta}{R_j}=\frac{60}{1 \times 10^3}=6 \times 10^{-2}$
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