MCQ
A transverse wave is passing through a string shown in figure. Mass density of the string is $1 \ kg/m^3$ and cross section area of string is $0.01\ m^2.$ Equation of wave in string is $y = 2sin (20t - 10x).$ The hanging mass is (in $kg$):-
  • A
    $40$
  • B
    $0.2$
  • $0.004$
  • D
    $0.00025$

Answer

Correct option: C.
$0.004$
c
$\mathrm{v}=\frac{\omega}{\mathrm{k}} \cdot$ Also $\mathrm{v}=\sqrt{\frac{\mathrm{T}}{\mu}}$

$v=\frac{20}{10}=\sqrt{\frac{M g}{1 \times 0.01}}$

$\mathrm{M}=0.004$

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