a
$y(x, t)=8.0 \sin \left(0.5 \pi x-4 \pi t-\frac{\pi}{4}\right)$
Compare with a standard wave equation,
$y=a \sin \left(\frac{2 \pi x}{\lambda}-\frac{2 \pi t}{T}+\phi\right)$
we get $\frac{2 \pi}{\lambda}=0.5 \pi$ or, $\lambda=\frac{2 \pi}{0.5 \pi}=4 \mathrm{m}$
$\frac{2 \pi}{T}=4 \pi$ or $, T=\frac{2 \pi}{4 \pi}=\frac{1}{2} \sec$
$v=1 / T=2 \mathrm{Hz}$
Wave velocity, $v=\lambda v=4 \times 2=8 \mathrm{m} / \mathrm{sec}$