MCQ
A travelling wave in a stretched string is described by the equation $y = A\sin (kx - \omega t)$. The maximum particle velocity is
- ✓$A\omega$
- B$A\omega/k$
- C$d\omega/dk$
- D$x/t$
✓
Answer
Correct option: A.
$A\omega$
a
(a)Given $y = A\sin (kx - \omega t)$
$ \Rightarrow $ $v = \frac{{dy}}{{dt}}$= $ - A\omega \cos (kx - \omega \,t)$: ==> ${v_{\max }} = A\omega $
(a)Given $y = A\sin (kx - \omega t)$
$ \Rightarrow $ $v = \frac{{dy}}{{dt}}$= $ - A\omega \cos (kx - \omega \,t)$: ==> ${v_{\max }} = A\omega $
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