MCQ
A triangle $ABC$ in which $AB = AC = 4\ cm$ and $\angle\text{A}=90^\circ,$ has an area of:
- A$16\ cm^2$
- ✓$8\ cm^2$
- C$12\ cm^2$
- D$4\ cm^2$
✓
Answer
Correct option: B.
$8\ cm^2$
According to question, in given right-angled triangle $AB$ and $AC$ are Base and Perpendicular respectively.
$\text{Area}=\frac{1}{2}\times4\times4$
$= 8\ cm^2$.
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