MCQ
A two-digit number $\overline{a b}$ is called almost prime if one obtains a two-digit prime number by changing at most one of its digits $a$ and $b$. (For example, $18$ is an almost prime number because $13$ is a prime number). Then the number of almost prime two-digit numbers is
  • A
    $56$
  • B
    $75$
  • C
    $87$
  • $90$

Answer

Correct option: D.
$90$
d
(d)

Since in the group of first $10$ two digit number $10-19$, has atleast $1$ prime number similarly in other groups of 10 two digits numbers

$20-29$, 30-39, 40-49, 50-59, 60-69, 70-79, $80-89$ and $90-99$ have almost $1$ prime numbers.

So, the number of almost prime two-digit number is $90 .$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The term independent of $x$ in the expansion of $\left( {\frac{1}{{60}} - \frac{{{x^8}}}{{81}}} \right).{\left( {2{x^2} - \frac{3}{{{x^2}}}} \right)^6}$ is equal to
The product of the perpendiculars drawn from the points $( \pm \sqrt {{a^2} - {b^2},} 0)$ on the line$\frac{x}{a}\cos \theta + \frac{y}{b}\sin \theta = 1$, is
In a triangle ABC, a = 4, b = 3, $\angle\text{A}=60^{\circ}$ then c is a root of the equation:
Total number of four digit odd numbers that can be formed using 0, 1, 2, 3, 5, 7 (using repetition allowed) are:
Let $a, b, x$ be positive real numbers with $a \neq 1$, $x \neq 1$, ab $\neq 1$. Suppose $\log _{ a } b =10$, and $\frac{\log _{ a } x \log _{ x }\left(\frac{ b }{ a }\right)}{\log _{ x } b \log _{ ab } x }=\frac{ p }{ q }$, where $p$ and $q$ are positive integers which are coprime. Then $p+q$ is
The equation of the circle $x^2 + y^2 + 2gx + 2fy + c = 0$ will represent a real circle if:
If $S$ is a set of $P(x)$ is polynomial of degree $ \le 2$ such that $P(0) = 0,$$P(1) = 1$,$P'(x) > 0{\rm{ }}\forall x \in (0,\,1)$, then
${\cos ^2}\left( {\frac{\pi }{6} + \theta } \right) - {\sin ^2}\left( {\frac{\pi }{6} - \theta } \right) = $
The coefficient of $x^5$ in the expansion of $(1+\text{x})^{21}+(1+\text{x})^{22}+...+(1+\text{x})^{30}$
If the value of $\frac{3 \cos 36^{\circ}+5 \sin 18^{\circ}}{5 \cos 36^{\circ}-3 \sin 18^{\circ}}$ is $\frac{a \sqrt{5}-b}{c}$ where $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are natural numbers and $\operatorname{gcd}(\mathrm{a}, \mathrm{c})=1$, then $\mathrm{a}+\mathrm{b}+\mathrm{c}$ is equal to :