Question
A uniform chain (mass $M,$ length $L$) is released from rest from a smooth horizontal surface as shown in the figure. Velocity of the chain at the instant it completely comes out of the table will be
✓
Answer
$\frac{1}{2}M{V^2} - Mg\frac{L}{2} = - \frac{M}{2}.g.\frac{L}{4}$ (energy conservation)
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