
$A=\frac{1}{2} \frac{(\text { stress })^{2}}{Y}=$ constant
$\frac{_{1}}{2} \frac{\left(\frac{M}{L} \frac{x}{A} g\right)^{2}}{Y}=$ constant
$(I)$ the loss of gravitational potential energy of mass $M$ is $Mgl$
$(II)$ the elastic potential energy stored in the wire is $Mgl$
$(III)$ the elastic potential energy stored in wire is $\frac{1}{2}\, Mg l$
$(IV)$ heat produced is $\frac{1}{2}\, Mg l$
Correct statement are :-