Question
A uniform electric field of $10 \mathrm{NC}^{-1}$ exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of 50cm.
✓
Answer
$\text{E}=10\text{n/c},\ \text{S}=50\text{cm}=0.1\text{m}$$\text{E}=\frac{\text{dV}}{\text{dr}}$
Or,
$\text{V}=\text{E}\times\text{r}$
$\text{r}=10\times0.5$
$=5\text{cm}$
Or,
$\text{V}=\text{E}\times\text{r}$
$\text{r}=10\times0.5$
$=5\text{cm}$
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