A uniform heavy rod of weight $10\, {kg} {ms}^{-2}$, crosssectional area $100\, {cm}^{2}$ and length $20\, {cm}$ is hanging from a fixed support. Young modulus of the material of the rod is $2 \times 10^{11} \,{Nm}^{-2}$. Neglecting the lateral contraction, find the elongation of rod due to its own weight. (In $\times 10^{-10} {m}$)
JEE MAIN 2021, Diffcult
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We know,

$\Delta \ell=\frac{{WL}}{2 {AY}}$

$\Delta \ell=\frac{10 \times 1}{2 \times 5} \times 100 \times 10^{-4} \times 2 \times 10^{11}$

$\Delta \ell=\frac{1}{2} \times 10^{-9}=5 \times 10^{-10}\, {m}$

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