- A

- B

- ✓

- D






magnetic moment of current carrying coil is a vector and its direction is given by right hand thumbrule, for rectangular loop, $\overrightarrow{B}$ at centre due to current in loop and $\overrightarrow{\mathrm{M}}$ are always parallel.
Hence, $(c)$ corresponds to stable equilibrium. 
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$(i)\,\,\,\,\,{y_1} = A\,\cos \,\,2\pi \,\left( {{n_1}t\, + \,\frac{x}{{{\lambda _1}}}} \right)$
$(ii)\,\,\,\,\,{y_2} = A\,\cos \,\,2\pi \,\left( {{n_1}t\, + \,\frac{x}{{{\lambda _1}}} + \pi } \right)$
$(iii)\,\,\,\,\,{y_3} = A\,\cos \,\,2\pi \,\left( {{n_2}t\, + \,\frac{x}{{{\lambda _2}}}} \right)$
$(iv)\,\,\,\,\,{y_4} = A\,\cos \,\,2\pi \,\left( {{n_2}t\, - \,\frac{x}{{{\lambda _2}}}} \right)$
The pairs of waves which will produce destructive interference and stationary waves respectively in a medium, are

${I_p} = 0.125\,{V_p} - 7.5$
If on applying $-3 $ volt potential at grid and $ 300 V$ potential at plate, the plate current is found to be $ 5mA$ , then amplification factor of the triode is