MCQ
A uniform sphere of weight $W$ and radius $3\,m$ is being held by a string of length $2\,m$ , attached to a frictionless wall as shown in the figure. The tension in the string will be


- ✓$5\,W/4$
- B$15\,W/4$
- C$15\,W/16$
- D$5\,W/3$

$\cos \theta=3 / 5 \Rightarrow \quad \theta=53^{\circ}$
$\mathrm{T}=\frac{\mathrm{W}}{\sin 53^{\circ}}=\frac{5}{4} \mathrm{W}$
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