A unit vector in the xy - plane which is perpendicular to 4i - 3j… - Vidyadip

MCQ

A unit vector in the $xy - $ plane which is perpendicular to $4i - 3j + k$ is

A
$\frac{{i + j}}{{\sqrt 2 }}$
✓
$\frac{1}{5}(3i + 4j)$
C
$\frac{1}{5}\,(3i - 4j)$
D
None of these

✓

Answer

Correct option: B.

$\frac{1}{5}(3i + 4j)$

b
(b) ${x^2} + {y^2} = 1$

Let vector be $xi + yj,$ then $4x - 3y = 0$

$ \Rightarrow 4x = 3y \Rightarrow x = \frac{3}{5},\,\,y = \frac{4}{5},$

Hence the required vector is $\frac{1}{5}(3i + 4j).$

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