
- A$2/\sqrt 3$
- B$4/\sqrt 3$
- ✓$2$
- DNone

In second cylinder the component of Area vector along the direction of rain is $A_{1} \cos 60^{\circ}=$$A_{1} / 2 .$ So, rate of water collection in second container is $0.5 A_{1} \times$ velocity of rain. The ratio of water collection is $2 .$
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$(i)$ The source may be moving towards the observer with a velocity of $30\,ms^{-1}$
$(ii)$ The source may be moving towards the observer with a velocity of $33\,ms^{-1}$
$(iii)$ The observer may be moving towards the source with a velocity of $30\,ms^{-1}$
$(iv)$ The observer may be moving towards the source with a velocity of $33\,ms^{-1}$
$(a)$ $\left(x^2-v t\right)^2$
$(b)$ $\log \left[\frac{(x+v t)}{x_0}\right]$
$(c)$ $e^{\left\{-\frac{(x+v t)}{x_0}\right\}^2}$
$(d)$ $\frac{1}{x+v t}$