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Electric Current in Conductors — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysicsElectric Current in Conductors5 Marks
Question
A voltmeter coil has resistance $50.0\Omega$ and a resistor of $1.15\text{k}\Omega$ is connected in series. It can read potential differences up to 12 volts. If this same coil is used to construct an ammeter that can measure currents up to 2.0A, what should be the resistance of the shunt used?
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Answer



$\text{R}_\text{eff}=(1150+50)\Omega=1200\Omega$
$\text{i}=\Big(\frac{12}{1200}\Big)\text{A}=0.01\text{A}.$
(The resistor of $50\Omega$ can tolerate)
Let R be the resistance of sheet used.
The potential across both the resistors is same.
$0.01\times50=1.99\times\text{R}$
$\Rightarrow\text{R}=\frac{0.01\times50}{1.99}=\frac{50}{199}=0.251\Omega$

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