MCQ
A wave travelling in positive $x-$direction with $A = 0.2\;m$ has a velocity of $360 \;m/sec.$ if $\lambda = 60\;m,$ then correct expression for the wave is
  • A
    $y = 0.2\sin \,\left[ {2\pi \left( {6t + \frac{x}{{60}}} \right)} \right]$
  • B
    $y = 0.2\sin \,\left[ {\pi \left( {6t + \frac{x}{{60}}} \right)} \right]$
  • $y = 0.2\sin \,\left[ {2\pi \left( {6t - \frac{x}{{60}}} \right)} \right]$
  • D
    $y = 0.2\sin \,\left[ {\pi \left( {6t - \frac{x}{{60}}} \right)} \right]$

Answer

Correct option: C.
$y = 0.2\sin \,\left[ {2\pi \left( {6t - \frac{x}{{60}}} \right)} \right]$
c
(c) A wave travelling in positive $x-$direction may be represented as

$y = A\sin \frac{{2\pi }}{\lambda }\,(v\,t - x)$.

On putting values $y = 0.2\sin \frac{{2\pi }}{{60}}(360\,t - x)$

$\Rightarrow$ $y = 0.2\sin 2\pi \,\left( {6\,t - \frac{x}{{60}}} \right)$

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