MCQ
A weak acid $HX$ has the dissociation constant $1 \times {10^{ - 5}}\,M$. It forms a salt $NaX$ on reaction with alkali. The degree of hydrolysis of $ 0.1 \,M $ solution of $NaX $ is......$\%$
- A$0.0001$
- ✓$0.01$
- C$0.1$
- D$0.15$
${K_h} = \frac{{{{10}^{ - 14}}}}{{{{10}^{ - 5}}}}$ so $h = \sqrt {\frac{{{{10}^{ - 9}}}}{{{{10}^{ - 1}}}}} = {10^{ - 4}}$
$100 \times {10^{ - 4}} = {10^{ - 2}}$
So, $0.01\%.$
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