MCQ
A weak acid $HX$ has the dissociation constant $1 \times {10^{ - 5}}\,M$. It forms a salt $NaX$ on reaction with alkali. The degree of hydrolysis of $ 0.1 \,M $ solution of $NaX $ is......$\%$
  • A
    $0.0001$
  • $0.01$
  • C
    $0.1$
  • D
    $0.15$

Answer

Correct option: B.
$0.01$
(b) ${X^ - } + {H_2}O⇌ HX + O{H^ - }$

${K_h} = \frac{{{{10}^{ - 14}}}}{{{{10}^{ - 5}}}}$ so $h = \sqrt {\frac{{{{10}^{ - 9}}}}{{{{10}^{ - 1}}}}} = {10^{ - 4}}$

$100 \times {10^{ - 4}} = {10^{ - 2}}$

So, $0.01\%.$

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