MCQ
A weak acid of dissociation constant $10^{-5}$ is being titrated with aqueous $NaOH$ solution. The $pH$ at the point of one-third neutralization of the acid will be:-
- A$5 + \log 2 -\log 3$
- ✓$5 -\log 2$
- C$5 -\log 3$
- D$5 -\log 6$
✓
Answer
Correct option: B.
$5 -\log 2$
b
$\mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log \frac{1 / 3}{2 / 3}$
$\mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log \frac{1 / 3}{2 / 3}$
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